The power spectrum at the input of the correlator when the telescope is
pointed at the source of interest,
, and at the reference target,
, can be written as
![]()
where

,
, and
are assumed not to vary significantly
with frequency over the bandpass of the spectrometer.
Taking ratios and doing appropriate algebra,
![]()
Since the gain is the unknown that one aims to remove by this calibration,
it is assumed not vary with power level. One then obtains the difference
between the signal spectrum and the reference spectrum:
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The ratio of the mean power levels can be
obtained from
a broadband detector or power meter or similar device. In general the spectrum
will have poor baselines because
the system gain is invariably non-linear to some small degree and the
non-linearity is
a function of frequency.
The system temperatures for the reference spectrum and
the signal spectrum, respectively, are
![]()
Equation 1 gives the signal, both line and continuum, by which the
source differs from the reference:

Since spectral lines are typically weak,
and
, so that
![]()
and therefore
![]()
This allows us to rewrite equation 1 as
![]()
and suggests the definition of a normalized calibrated spectrum as
![]()
so that
![]()
The expected r.m.s. noise in
is calculated from
equation 2:

Substituting in the radiometer equation for the normalized spectrum
![]()
we get
![]()
which, assuming that the sig and ref
integration times are the same, leads to the result
![]()
Generally, the sig/ref duty cycle is 50%, and the total
integration sig+ref integration time,
is used in the
radiometer equation, in which case
![]()
A tidy way to avoid having to worry about the constant in the radiometer
equation, and also to handle cases where the two spectra don't have the same
integration times, is to define the integration time for the
calibrated spectrum so that the constant in the radiometer equation remains
unity:
![]()
so that

In the case of a 50% duty cycle leads to
.
We have two spectra
and
which we want to combine optimally
so that the combined spectrum
has the minimum noise. To do this we
combine them with weights
and
so that
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The proof below shows that this requires that
![]()
To apply this result, we note from equation 9 above that
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Since any constant divides out, we can choose
and thus

Using equation 4 to replace
with
and equation 16 (see below) to replace the denominator, we obtain
the equivalent normalized spectrum:

Proof: The noise in the combined spectrum is

We want to minimize this noise by an optimum choice of
:

which proves equation 10.
With equation 10, equation 15 reduces to:

Using equation 9, and cancelling out
,
we can write this as
![]()
where
and
are defined as the effective system
temperature and integration time of the combined spectrum.
If
, then proper scaling of the combined spectrum
requires that
, and thus that
![]()
It then follows from equation 16 that
